Skip to content

Maths Formula Compendium

Trigonometry

Name \(0\degree\) \(30\degree (\frac{\pi}{6})\) \(45\degree (\frac{\pi}{4})\) \(60\degree (\frac{\pi}{3})\) \(90\degree (\frac{\pi}{2})\) \(120\degree (\frac{2\pi}{3})\) \(135\degree (\frac{3\pi}{4})\) \(150\degree (\frac{5\pi}{6})\) \(180\degree (\pi)\)
\(\sin\) \(0\) \(\frac{1}{2}\) \(\frac{1}{\sqrt{2}}\) \(\frac{\sqrt{3}}{2}\) \(1\) \(\frac{\sqrt{3}}{2}\) \(\frac{1}{\sqrt{2}}\) \(\frac{1}{2}\) \(0\)
\(\cos\) \(1\) \(\frac{\sqrt{3}}{2}\) \(\frac{1}{\sqrt{2}}\) \(\frac{1}{2}\) \(0\) \(-\frac{1}{2}\) \(-\frac{1}{\sqrt{2}}\) \(-\frac{\sqrt{3}}{2}\) \(-1\)
\(\tan\) \(0\) \(\frac{1}{\sqrt{3}}\) \(1\) \(\sqrt{3}\) \(\infty\) \(-\sqrt{3}\) \(-1\) \(-\frac{1}{\sqrt{3}}\) \(0\)
\(\cot\) \(\infty\) \(\sqrt{3}\) \(1\) \(\frac{1}{\sqrt{3}}\) \(0\) \(-\frac{1}{\sqrt{3}}\) \(-1\) \(-\sqrt{3}\) \(-\infty\)
\(\sec\) \(1\) \(\frac{2}{\sqrt{3}}\) \(\sqrt{2}\) $ 2 $ \(\infty\) \(-2\) \(-\sqrt{2}\) \(-\frac{2}{\sqrt{3}}\) \(-1\)
\(\cosec\) \(\infty\) \(2\) \(\sqrt{2}\) \(\frac{2}{\sqrt{3}}\) \(1\) \(\frac{2}{\sqrt{3}}\) \(\sqrt{2}\) \(2\) \(\infty\)

Trigonometric Identities

$\sin(A + B) = \sin A \cos B + \cos A \sin B$
$\sin(A - B) = \sin A \cos B - \cos A \sin B$
$\cos(A + B) = \cos A \cos B - \sin A \sin B$
$\cos(A - B) = \cos A \cos B + \sin A \sin B$
$\sin C + \sin D = 2 \sin \frac{C + D}{2} \cos \frac{C - D}{2}$
$\sin C - \sin D = 2 \cos \frac{C + D}{2} \sin \frac{C - D}{2}$
$\cos C + \cos D = 2 \cos \frac{C + D}{2} \cos \frac{C - D}{2}$
$\cos C - \cos D = -2 \sin \frac{C + D}{2} \sin \frac{C - D}{2}$
$\sin(A + B) \sin(A - B) = \sin^2 A - \sin^2 B$
$\cos(A + B) \cos(A - B) = \cos^2 A - \sin^2 B$
$\tan A - \tan B = \frac{\sin(A - B)}{\cos A \cos B}$
$\cot A - \cot B = \frac{-\sin(A - B)}{\sin A \sin B}$
\[ \sin(A + B + C) = \sin A \cos B \cos C + \cos A \sin B \cos C + \cos A \cos B \sin C - \sin A \sin B \sin C \]
\[ \cos(A + B + C) = \cos A \cos B \cos C - \cos A \sin B \sin C - \sin A \cos B \sin C - \sin A \sin B \cos C \]
\[ \tan(A + B + C) = \frac{\tan A + \tan B + \tan C - \tan A \tan B \tan C}{1 - \tan A \tan B - \tan B \tan C - \tan C \tan A} \]

Double Angle Formulas

$$ \begin{aligned} \sin 2A &= 2 \sin A \cos A = \frac{2 \tan A}{1 + \tan^2 A} \\ \cos 2A &= \cos^2 A - \sin^2 A = 2\cos^2 A - 1 = 1 - 2\sin^2 A = \frac{1 - \tan^2 A}{1 + \tan^2 A} \end{aligned} $$
$$ \begin{aligned} \sin 3A &= 3 \sin A - 4 \sin^3 A \\ \cos 3A &= 4 \cos^3 A - 3 \cos A \end{aligned} $$
$$ \begin{aligned} \tan 2A &= \frac{2 \tan A}{1 - \tan^2 A} \\ \tan 3A &= \frac{3 \tan A - \tan^3 A}{1 - 3 \tan^2 A} \end{aligned} $$

Product-to-Sum Formulas

  • \(2 \sin x \sin y = \cos(x - y) - \cos(x + y)\)
  • \(2 \cos x \cos y = \cos(x + y) + \cos(x - y)\)
  • \(2 \sin x \cos y = \sin(x + y) + \sin(x - y)\)
  • \(2 \cos x \sin y = \sin(x + y) - \sin(x - y)\)

Pythagorean Identities

  • \(\sin^2 \theta + \cos^2 \theta = 1\)
  • \(1 + \tan^2 \theta = \sec^2 \theta\)
  • \(1 + \cot^2 \theta = \csc^2 \theta\)
$\tan(x + y) = \frac{\tan x + \tan y}{1 - \tan x \tan y}$
$\tan(x - y) = \frac{\tan x - \tan y}{1 + \tan x \tan y}$
$\cot(x + y) = \frac{\cot x \cot y - 1}{\cot x + \cot y}$
$\cot(x - y) = \frac{\cot x \cot y + 1}{\cot y - \cot x}$
  • \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\)
  • \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\)

General Solutions

Basic Cases

  • \(\sin \theta = 0 \implies \theta = n\pi\)
  • \(\cos \theta = 0 \implies \theta = (2n + 1)\frac{\pi}{2}\)
  • \(\tan \theta = 0 \implies \theta = n\pi\)

Equality Cases

  • \(\sin \theta = \sin \beta \implies \theta = n\pi + (-1)^n \beta\)
  • \(\cos \theta = \cos \beta \implies \theta = 2n\pi \pm \beta\)
  • \(\tan \theta = \tan \beta \implies \theta = n\pi + \beta\)

Derived Cases

  • \(\sin^2 \theta = \sin^2 \beta \implies \theta = n\pi \pm \beta\)
  • \(\cos^2 \theta = \cos^2 \beta \implies \theta = n\pi \pm \beta\)
  • \(\tan^2 \theta = \tan^2 \beta \implies \theta = n\pi \pm \beta\)

Secant and Cosine Properties

  • \(-\cos \theta = \cos(\pi - \theta)\)
  • \(-\sec \theta = \sec(\pi - \theta)\)
  • \(\cos(- \theta) = \cos\theta\)
  • \(\sec(-\theta) = \sec\theta\)

Transformation Rule (TR)

\((\frac{n\pi}{2} + \theta)\)

  • If \(n\) is odd \(\Rightarrow\) TR will change.

\((n\pi + \theta)\)

  • If \(n\) is odd/even \(\Rightarrow\) TR will not change.

Inverse Trigonometry

Domain (value) (\(x\)) Range (Angle) (\(\theta\))
\(\sin^{-1}x\) \([-1,1]\) \([-\pi/2, \pi/2]\)
\(\cos^{-1}x\) \([-1,1]\) \([0, \pi]\)
\(\tan^{-1}x\) \(\mathbb{R}\) \((-\pi/2, \pi/2)\)
\(\cot^{-1}x\) \(\mathbb{R}\) \((0, \pi)\)
\(\sec^{-1}x\) \((-\infty,-1] \cup [1,\infty)\) \([0,\pi] \setminus \{\pi/2\}\)
\(\cosec^{-1}x\) \((-\infty,-1] \cup [1,\infty)\) \([-\pi/2,0) \cup (0,\pi/2]\)
Property 1 Property 2
\(\sin^{-1}(\sin\theta) = \theta\) \(\sin(\sin^{-1}x) = x\)
\(\cos^{-1}(\cos\theta) = \theta\) \(\cos(\cos^{-1}x) = x\)
\(\tan^{-1}(\tan\theta) = \theta\) \(\tan(\tan^{-1}x) = x\)
\(\cosec^{-1}(\cosec\theta) = \theta\) \(\cosec(\cosec^{-1}x) = x\)
\(\sec^{-1}(\sec\theta) = \theta\) \(\sec(\sec^{-1}x) = x\)
\(\cot^{-1}(\cot\theta) = \theta\) \(\cot(\cot^{-1}x) = x\)

These compositions use the principal ranges in the table: for example, \(\sin^{-1}(\sin\theta)=\theta\) only when \(\theta\in[-\pi/2,\pi/2]\), and \(\cos^{-1}(\cos\theta)=\theta\) only when \(\theta\in[0,\pi]\).

Property 3
\(\sin^{-1}(-x) = -\sin^{-1}(x)\) \(\cos^{-1}(-x) = \pi -\cos^{-1}(x)\)
\(\tan^{-1}(-x) = -\tan^{-1}(x)\) \(\cot^{-1}(-x) = \pi -\cot^{-1}(x)\)
\(\cosec^{-1}(-x) = -\cosec^{-1}(x)\) \(\sec^{-1}(-x) = \pi -\sec^{-1}(x)\)
Property 4
\(\sin^{-1}(\frac{1}{x}) = \cosec^{-1}(x)\)
\(\cos^{-1}(\frac{1}{x}) = \sec^{-1}(x)\)
\(\tan^{-1}(\frac{1}{x}) = \cot^{-1}(x),\quad x>0\)

The reciprocal identities for inverse sine and inverse cosine require \(|x|\geq1\).

For \(x<0\), \(\tan^{-1}(1/x)=\cot^{-1}(x)-\pi\) with the stated principal range for \(\cot^{-1}\).

Property 5
\(\sin^{-1}x + \cos^{-1}x = \frac{\pi}{2}\)
\(\tan^{-1}x + \cot^{-1}x = \frac{\pi}{2}\)
\(\sec^{-1}x + \cosec^{-1}x = \frac{\pi}{2}\)
Property 6
\(\sin^{-1}x + \sin^{-1}y = \sin^{-1} \big(x\sqrt{1-y^2} + y\sqrt{1-x^2}\big)\)
\(\sin^{-1}x - \sin^{-1}y = \sin^{-1} \big(x\sqrt{1-y^2} - y\sqrt{1-x^2}\big)\)
Property 7
\(\cos^{-1}x + \cos^{-1}y = \cos^{-1} \big(xy - \sqrt{1-x^2} \sqrt{1-y^2}\big)\)
\(\cos^{-1}x - \cos^{-1}y = \cos^{-1} \big(xy + \sqrt{1-x^2} \sqrt{1-y^2}\big)\)

For Properties 6 and 7, use these identities only when the resulting angle is in the principal inverse-trigonometric range; otherwise apply the appropriate branch adjustment.

Property 8
\(\tan^{-1}x - \tan^{-1}y \equiv \tan^{-1}\Big(\frac{x-y}{1+xy}\Big) \pmod{\pi}\)
\(\tan^{-1}x + \tan^{-1}y \equiv \tan^{-1}\Big(\frac{x+y}{1-xy}\Big) \pmod{\pi}\)

These sum-and-difference identities assume the denominators are nonzero. Inverse-trigonometric results use the principal ranges above; adjust by a multiple of \(\pi\) when needed.

Property 9

$\sin\big(2\sin^{-1}x\big) = 2x\sqrt{1-x^2}$
$\sin\big(3\sin^{-1}x\big) = 3x-4x^3$
$\cos\big(2\cos^{-1}x\big) = 2x^2-1$
$\cos\big(3\cos^{-1}x\big) = 4x^3-3x$
$$ \begin{aligned} 2\tan^{-1}x &\equiv \tan^{-1}\Big(\frac{2x}{1-x^2}\Big) \pmod{\pi} \\ 3\tan^{-1}x &\equiv \tan^{-1}\Big(\frac{3x-x^3}{1-3x^2}\Big) \pmod{\pi} \end{aligned} $$

Property 10

\[ \begin{aligned} \sin\big(2\tan^{-1}x\big) &= \frac{2x}{1+x^2} \\ \cos\big(2\tan^{-1}x\big) &= \frac{1-x^2}{1+x^2} \end{aligned} \]

\(1-\cos\theta = 2 \sin^2(\theta/2)\)

\(1+ \cos\theta = 2\,\cos^2(\theta/2)\)

\(\sin\theta = 2\sin(\theta/2)\cos(\theta/2)\)

\(2\sin^{-1}x + \sin^{-1}(-x) = \cos^{-1}x\)

$$ \begin{split}\cos2\theta &= \cos^2\theta - \sin^2\theta \\& = 2\cos^2\theta -1 \\ &= 1 - 2\sin^2\theta \end{split} $$
Expression and Substitution
Expression Substitution Substitution
\(a^2 + x^2\) \(x = a\tan\theta\) \(x = a\cot\theta\)
\(a^2-x^2\) \(x=a\sin\theta\) \(x=a\cos\theta\)
\(x^2-a^2\) \(x=a\sec\theta\) \(x=a\cosec\theta\)
\(\sqrt{\frac{a-x}{a+x}}\) \(x=a\cos2\theta\)
\(\sqrt{\frac{a^2+x^2}{a^2-x^2}}\) \(x=a^2\cos2\theta\)

Differentiation

$\frac{d}{dx} x^n = n x^{n-1}$
$\frac{d}{dx} a^x = a^x \ln a$
$\frac{d}{dx} \log_e x = \frac{1}{x}$
$\frac{d}{dx} \log_a x = \frac{1}{x \ln a}$
$\frac{d}{dx} e^x = e^x$
$\frac{d}{dx} \sin x = \cos x$
$\frac{d}{dx} \cos x = -\sin x$
$\frac{d}{dx} \tan x = \sec^2 x$
$\frac{d}{dx} \sec x = \sec x \tan x$
$\frac{d}{dx} \cot x = -\csc^2 x$
$\frac{d}{dx} \cosec x = -\cosec x \cot x$
$\log m^n = n \log m$
$\log m + \log n = \log (mn)$
$\log m - \log n = \log \left(\frac{m}{n}\right)$
$\log e = 1$, $\log_a a = 1$
$\log_a b = \frac{1}{\log_b a}$
$\frac{d}{dx} \sin^{-1} x = \frac{1}{\sqrt{1 - x^2}}$
$\frac{d}{dx} \cos^{-1} x = \frac{-1}{\sqrt{1 - x^2}}$
$\frac{d}{dx} \tan^{-1} x = \frac{1}{1 + x^2}$
$\frac{d}{dx} \cot^{-1} x = \frac{-1}{1 + x^2}$
$\frac{d}{dx} \sec^{-1} x = \frac{1}{x \sqrt{x^2 - 1}}$
$\frac{d}{dx} \cosec^{-1} x = \frac{-1}{x \sqrt{x^2 - 1}}$
  • \(a^{\log_a x} = x\)
  • \(x^{\log_a y} = y^{\log_a x}\)

Chain Rule

If a variable \(z\) depends on the variable \(y\), which itself depends on the variable \(x\) (that is, \(y\) and \(z\) are dependent variables), then \(z\) depends on \(x\) as well, via the intermediate variable \(y\). In this case, the chain rule is expressed as:

$$ \frac{dz}{dx} = \frac{dz}{dy} \cdot \frac{dy}{dx} $$

Integration Formulas

Basic Integration Rules

  1. \(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\)
  2. \(\int \frac{1}{x} \, dx = \ln |x| + C\)
  3. \(\int e^x \, dx = e^x + C\)
  4. \(\int a^x \, dx = \frac{a^x}{\ln a} + C\)
  5. \(\int \sin x \, dx = -\cos x + C\)
  6. \(\int \cos x \, dx = \sin x + C\)
  7. \(\int \sec^2 x \, dx = \tan x + C\)
  8. \(\int \csc^2 x \, dx = -\cot x + C\)
  9. \(\int \sec x \tan x \, dx = \sec x + C\)
  10. \(\int \csc x \cot x \, dx = -\csc x + C\)
  11. \(\int \cot x \, dx = \ln |\sin x| + C\)
  12. \(\int \tan x \, dx = -\ln |\cos x| + C = \ln |\sec x| + C\)
  13. \(\int \sec x \, dx = \ln |\sec x + \tan x| + C\)
  14. \(\int \csc x \, dx = \ln |\csc x - \cot x| + C\)

Inverse Trigonometric Integrals

  1. \(\int \frac{1}{\sqrt{a^2 - x^2}} \, dx = \sin^{-1} \left(\frac{x}{a}\right) + C\)
  2. \(\int \frac{-1}{\sqrt{a^2 - x^2}} \, dx = \cos^{-1} \left(\frac{x}{a}\right) + C\)
  3. \(\int \frac{1}{x^2 + a^2} \, dx = \frac{1}{a} \tan^{-1} \left(\frac{x}{a}\right) + C\)
  4. \(\int \frac{-1}{x^2 + a^2} \, dx = \frac{1}{a} \cot^{-1} \left(\frac{x}{a}\right) + C\)
  5. \(\int \frac{1}{x \sqrt{x^2 - a^2}} \, dx = \frac{1}{a} \sec^{-1} \left|\frac{x}{a}\right| + C\)
  6. \(\int \frac{-1}{x \sqrt{x^2 - a^2}} \, dx = \frac{1}{a} \csc^{-1} \left|\frac{x}{a}\right| + C\)

Logarithmic and Advanced Integrals

  1. \(\int e^{x} \big(f(x) + f'(x)\big) \, dx = e^x f(x) + C\)
  2. \(\int \frac{dx}{\sqrt{x^2 + a^2}} = \ln |x + \sqrt{x^2 + a^2}| + C\)
  3. \(\int \frac{dx}{x^2 - a^2} = \frac{1}{2a} \ln \left|\frac{x - a}{x + a}\right| + C\)
  4. \(\int \frac{dx}{a^2 - x^2} = \frac{1}{2a} \ln \left|\frac{a + x}{a - x}\right| + C\)
  5. \(\int \frac{dx}{a^2 - x^2} = \frac{1}{2a} \ln \left|\frac{a + x}{x - a}\right| + C\)

Additional Properties

  • \(\int k f(x) \, dx = k \int f(x) \, dx\)
  • \(\int [f(x) \pm g(x)] \, dx = \int f(x) \, dx \pm \int g(x) \, dx\)
  • \(\int c \, dx = c x + C\)

Line Equations

  1. \(ax + by + c=0\)

    \(m = -a/b\) (Slope of line)

  2. One Point form of line

    \[ y - y_1 = m (x-x_1) \]
  3. Two point form of line

$$ y-y_1 = \frac{y_2-y_1}{x_2-x_1}(x-x_1) $$

  1. Intercept Form of line

$$ \frac{x}{a} + \frac{y}{b} = 1 $$

  1. Normal form of line

$$ x\cos \theta + y\sin\theta = P $$

  1. Point Slope form

$$ \begin{aligned} y &= mx+c \ m &= \frac{y_2-y_1}{x_2-x_1} \end{aligned} $$

Distance of a point from a line

\[ \text{Dist}_{PA}= \Bigg|{\frac{ax_1 + by_1 + c}{\sqrt{a^2+b^2}}}\Bigg| \]

Distance between two lines

\(y = mx + c_1 \qquad y= mx+c_2\)

\[ \text{d} = \Bigg| \frac{c_1 - c_2}{\sqrt{1+m^2}}\Bigg| = \Bigg|\frac{c_1 - c_2}{\sqrt{a^2+b^2}}\Bigg| \]

Angle between two lines

Where \(m_1\) and \(m_2\) are slopes of two lines.

\[ \tan\theta = \frac{m_2 - m_1}{1+m_2m_1} \]
  • If line \(l_1\) and \(l_2\) are orthogonal to each other, then. \(m_1m_2 = -1\)
  • Collinearity of points

Slope of \(AB\) = Slope of \(AC\)

Shapes CSA(Curved Surface Area), T(Total)SA, and volume

Frustum

\(\text{CSA} = \pi l (r_1+ r_2)\)

\(\text{TSA} = \pi r_1^2 + \pi r_2^2 + \pi l(r_1+r_2)\)

\(\text{Volume} = \frac{1}{3}\pi h (r_1^2 + r_2^2 + r_1r_2)\)

where \(l= \sqrt{h^2+(r_1-r_2)^2}\)

Adjoint and Inverse

$A(\text{adj} A) = \|A\| I_n = (\text{adj}) A$
$A^{-1} = \frac{1}{\|A\|} (\text{adj} A)$
$(A^\top)^{-1} = (A^{-1})^\top$
$\|A \enspace adj A\| = \|A\|^{n}$
$\|A^\top\| = \|A\| $
$AA^{-1} = I_n$
$(A^{-1})^{-1} = A$
$(AB)^{-1} = B^{-1}A^{-1}$
$\text{adj}\space AB = (\text{adj} B)(\text{adj} A)$
$\|AB\| = \|A\| \|B\|$
$\text{adj}A^\top = (\text{adj} A)\top$
$\|KA\| = K^n \|A\|$
$AA^{-1}=I$
$A^{-1}I = A^{-1}$
$\|\text{adj} A\| = \|A\|^{n-1}$
$\text{adj} \space(adj A) = \|A\|^{n-2} A$
$\|\text{adj} \space(adj A)\| = \|A\|^{(n-1)^{2}}$

Binomial Theorem

Initial conditions:

$^nc_0 = 1$
$^nc_1 = n$
$^nc_n = 1$
$^nc_{n-1} = n$

Basic expansion:

\[(x+a)^n = {^nc_0}x^na^0 + {^nc_1}x^{n-1}a^1 + {^nc_2}x^{n-2}a^2 + ... + {^nc_n}x^0a^n\]

Sum and difference formulas:

\[ (x+a)^n + (x-a)^n = 2\left[{^nc_0}x^na^0 + {^nc_2}x^{n-2}a^2 + {^nc_4}x^{n-4}a^4 + \cdots\right] \]
\[ (x+a)^n - (x-a)^n = 2\left[{^nc_1}x^{n-1}a^1 + {^nc_3}x^{n-3}a^3 + {^nc_5}x^{n-5}a^5 + \cdots\right] \]

Number of terms:

When n is odd When n is even
(x+a)^n + (x-a)^n \((\frac{n+1}{2})\) terms \((\frac{n}{2})\) terms
(x+a)^n - (x-a)^n \((\frac{n+1}{2})\) terms \((\frac{n}{2})\) terms

General Term and Middle Term

General term: \(t_{r+1} = {^nc_r}x^{n-r}a^r\)

Middle term occurs at:

  • If n is odd: \((\frac{n+1}{2})\) & \((\frac{n+3}{2})\) terms

  • If n is even: \((\frac{n}{2}+1)\) terms

Coefficient Tables

Coefficient of Binomial Expression is
\((r+1)^{\text{th}}\) \((1+x)^n\) \({^nc_r}\)
\(x^r\) \((1+x)^n\) \({^nc_r}\)
\(x^r\) \((1-x)^n\) \((-1)^r\enspace{^nc_r}\)
\((r+1)^{\text{th}}\) \((1-x)^n\) \((-1)^r\enspace{^nc_r}\)

Relations

$\frac{^nc_r}{^nc_{r-1}} = \frac{n-r+1}{r}$
$^nc_r = (\frac{n}{r})\enspace{^{n-1}c_{r-1}}$
$\frac{^nc_{r+1}}{^nc_r} = \frac{n-r}{r+1}$
$\frac{t_{r+1}}{t_r} = \frac{n-r+1}{r} \cdot \frac{a}{x}$

Probability

$P_r = \frac{n!}{(n-r)!}$
$C_r = \frac{n!}{(n-r)!r!}$
Operation Notation
A or B \(A \cup B\)
A and B \(A \cap B\)
A but not B \(A \cap \bar{B}\)
B but not A \(\bar{A} \cap B\)
Neither A nor B \(\bar{A} \cap \bar{B}\)
At least one of A,B,& C \(A \cup B \cup C\)
Exactly one of A,B \((A \cap \bar{B}) \cup (\bar{A} \cap B)\)
All Three of A,B,& C \(A \cap B \cap C\)
Exactly Two of A,B,& C \((A \cap B \cap \bar{C}) \cup (A \cap \bar{B} \cap C) \cup (\bar{A} \cap B \cap C)\)
Exactly One of A,B,& C \((A \cap \bar{B} \cap \bar{C}) \cup (\bar{A} \cap B \cap \bar{C}) \cup (\bar{A} \cap \bar{B} \cap C)\)

The probability formulas:

$$ \begin{split} P(A \cup B) &= P(A) + P(B) - P(A \cap B) \\ &= 1 - P(\overline{A \cup B}) \\ &= 1 - P(\overline{A} \cap \overline{B}) \\ &= 1 - P(\bar{A})P(\bar{B}) \end{split} $$
$$ \tag{\text{A and B are mutually exclusive}} P(A \cup B) = P(A) + P(B) $$
$$ \begin{split} P(A \cup B \cup C) &= P(A) + P(B) + P(C) - P(A \cap B) - P(B \cap C) - P(A \cap C) + P(A \cap B \cap C) \end{split} $$
$$ \tag{\text{A, B, and C are mutually exclusive}} P(A \cup B \cup C) = P(A) + P(B) + P(C) $$
  • Probability of occurrence of (A) only $\(P(A \cap \bar{B}) = P(A) - P(A \cap B)\)$

  • Probability of occurrence of (B) only $\(P(\bar{A} \cap B) = P(B) - P(A \cap B)\)$

  • P of occurrence of exactly one of A and B $\(P(A \cap \bar{B}) + P(\bar{A} \cap B) = P(A \cup B) - P(A \cap B)\)$

  • Three Events Occurring Simultaneously

$\(P(A \cap B \cap C)\)$

  • At Least Two Events: $\(P(A \cap B) + P(B \cap C) + P(C \cap A) - 2P(A \cap B \cap C)\)$

  • Exactly Two Out of Three Events: $\(P(A \cap B) + P(B \cap C) + P(C \cap A) - 3P(A \cap B \cap C)\)$

  • Exactly One Out of Three Events: $\(P(A) + P(B) + P(C) - 2P(A \cap B) - 2P(B \cap C) - 2P(C \cap A) + 3P(A \cap B \cap C)\)$

  • Exactly One Out of Two Events $\(P(A \cap \overline{B}) + P(\overline{A} \cap B)\)$

    • Simplified Form: $\(P(A) + P(B) - 2P(A \cap B) \implies P(A \cup B) - P(A \cap B)\)$
  • Conditional probability P of E given A is true

$$ \begin{split} P(E_i|A) &= P(E_i)P(A|E_i) \\ &= \sum_{i=1}^n P(E_i)P(A|E_i) \end{split} $$

\(P(A \cap B) = P(A)P(B|A) = P(B)P(A|B)\)

\(P(A \cap B \cap C \cap D) = P(A)P(B|A)P(C|A \cap B)P(D|A \cap B \cap C)\)

\[P(E_i | A) = \frac{P(E_i) P(A|E_i)}{\sum^n_{i=1}P(E_i) P(A|E_i)}\]

Also noting the card suit groupings shown in the image:

  • Hearts and Diamonds are grouped as Red
  • Spades and Clubs are grouped as Black

Mean Variance & Standard Deviation

  • \(p\) means success event
  • \(q\) means not a sucess event
$P(X = r) = {}_nC_r p^r q^{n-r}$
$Variance = npq$
$Mean = np$

Probability Relations: $\(P(X \leq x_i) = P(X = x_1) + P(X = x_2) + ... + P(X = x_i) = p_1 + p_2 + ... + p_i\)$

\[P(X < x_i) = P(X = x_1) + P(X = x_2) + ... + P(X = x_{i-1}) = p_1 + p_2 + ... + p_{i-1}\]
\[P(X \geq x_i) = P(X = x_i) + P(X = x_{i+1}) + ... + P(X = x_n) = p_i + p_{i+1} + ... + p_n\]
\[P(X > x_i) = P(X = x_{i+1}) + P(X = x_{i+2}) + ... + P(X = x_n) = p_{i+1} + p_{i+2} + ... + p_n\]
$P(X \geq x_i) = 1 - P(X < x_i)$
$P(X \leq x_i) = 1 - P(X > x_i)$
$P(X > x_i) = 1 - P(X \leq x_i)$
$P(X < x_i) = 1 - P(X \geq x_i)$
\[P(x_i \leq X \leq x_j) = P(X = x_i) + P(X = x_{i+1}) + ... + P(X = x_j)\]
\[P(x_i < X < x_j) = P(X = x_{i+1}) + P(X = x_{i+2}) + ... + P(X = x_{j-1})\]

Mean Formulas(Matehmatical expectation):

  • where \(f\) = frequency
$$ \begin{split} \overline{X} &= p_1x_1 + p_2x_2 + ... + p_nx_n \\ &= E(X) \\ &= \sum_{i=1}^n p_ix_i \\ &= \frac{f_1x_1}{N} + \frac{f_2x_2}{N} + ... + \frac{f_nx_n}{N} \end{split} $$
\[p_i = \frac{f_i}{N}\]

Variance Formula:

$$ \begin{split} Var(X) &= E(X^2) - \lbrace E(X)\rbrace^2 \\ &= \sum_{i=1}^n p_ix_i^2 - (\sum_{i=1}^n p_ix_i)^2 \end{split} $$
\[\frac{\sum x^2}{n} - (\frac{\sum x}{n})^2\]

Random Variable Property:

If \(X\) has mean \(E(X)\) and variance \(Var(X)\), then \(aX + b\) has mean \(aE(X) + b\) and variance \(a^2Var(X)\).

Standard Deviation:

$$ \begin{aligned} \sigma &= \sqrt{Var(X)} \\ \sigma^2 &= \frac{1}{N^2} \left[N\sum_{i=1}^n f_i x_i^2 - \left(\sum_{i=1}^n f_i x_i\right)^2\right] \end{aligned} $$

Arithmetic Progression (AP)

  • General Form: \(A, B, C\)

$\(2B = A + C\)$

Formulas:

  • \(t_n = a + (n-1)d\)
  • \(S_n = \frac{n}{2} \left[2a + (n-1)d \right]\)
  • \(S_n = \frac{n}{2} [a + a_n]\)
  • \(t_n = S_n - S_{n-1}\)

Arithmetic Mean (AM):

\(G = \frac{a+b}{2}\)


Geometric Progression (GP)

  • General Form: \(A, B, C\)

$\(B^2 = A \cdot C\)$

Formulas:

  • \(t_n = a \cdot r^{n-1}\)
  • \(S_n = a \frac{r^n - 1}{r - 1}, \, r \neq 1\)
  • \(S_\infty = \frac{a}{1-r}, \, |r| < 1\)

  • where \(r\) is common ratio

Geometric Mean (GM):

  • Single Mean Between \(a\) and \(b\): \(G = \sqrt{ab}\)
  • Multiple Means:
  • \(G_1 = ar^1\)
  • \(G_2 = ar^2\)
  • \(G_3 = ar^3\)
  • \(r = \sqrt[n+1]{\frac{b}{a}}\)

AP, GP, HP Relation:

\[AP \geq GP \geq HP\]

Special Sequences:

  1. Sum of Natural Numbers:
$$ 1 + 2 + 3 + \dots + n = \frac{n(n+1)}{2} $$
  1. Sum of Squares of Natural Numbers:
$$ 1^2 + 2^2 + 3^2 + \dots + n^2 = \frac{n(n+1)(2n+1)}{6} $$
  1. Sum of Cubes of Natural Numbers:
$$ 1^3 + 2^3 + 3^3 + \dots + n^3 = \left[\frac{n(n+1)}{2}\right]^2 $$

Homogeneous and Non homogeneous equations solutions

NON-HOMOGENEOUS
$AX = B$
Unique Solution
  1. $\text{adj}(A)B = 0 \implies \text{Infinite Solutions}$
  2. $\text{adj}(A)B \neq 0 \implies \text{No Solution}$
 
 
When $|A| \neq 0$
 
When $|A| = 0$
HOMOGENEOUS
$AX = 0$
Trivial solution $x = y = z = 0 \enspace $:
  1. $\text{Infinite Solutions}$ put $z = k$ and solve

Finding Log

  1. Given we need to find \(\log\) of \(\log 15.27\)

    • Move the decimal after 1st digit and introduce power of 10.
    \[ \log \textcolor{#f56c42}1.\textcolor{#f56c42}5\textcolor{#ad42f5}2\textcolor{#f542bc}7 \times 10^{\textcolor{#42f5f2}1} \]

    When the decimal is moved in left/right: $$ (-)\medspace \overrightarrow{\text{introduce negative powers}} \qquad \overleftarrow{\text{introduce positive powers}} \medspace(+) $$

  2. Look for \(\textcolor{#f56c42}{15}\)th row and column with label \(\textcolor{#ad42f5}2\). which is \(\bold{\textcolor{#07fc03}{1818}}\).

  3. Add Mean difference from column \(\textcolor{#f542bc}7\) in the corresponding row. which is \(\textcolor{#07fc03}{20}\)

    \[ 1818 + 20 = \bold{\textcolor{#07fc03}{1838}} \]
  4. Write the exponent, insert decimal and write the value calculated in Step 3.

    \[ \textcolor{#42f5f2}1.\textcolor{#07fc03}{1838} \]
  5. So \(\log 15.27 = \bold{\textcolor{#07fc03}{1.1838}}\)

Finding AntiLog

  1. Given we need to find Antilog of \(15.5932\) $$ \begin{aligned} \log k &= 15.5932 \ k &= \operatorname{Antilog}(\medspace \textcolor{#42f5f2}{15}\textcolor{#f56c42}{.59}\textcolor{#ad42f5}3\textcolor{#f542bc}2\medspace) \end{aligned} $$

  2. Look for \(0\textcolor{#f56c42}{.59}\)th row and column with label \(\textcolor{#ad42f5}3\). Which is \(\bold{\textcolor{#07fc03}{3917}}\).

  3. Add Mean difference from column \(\textcolor{#f542bc}2\) to previous result. Which is \(\textcolor{#07fc03}2\)

    \[ 3917 + 2 = \bold{\textcolor{#07fc03}{3919}} \]
  4. Add \(1\) to characteristic \(\textcolor{#42f5f2}{15} = \textcolor{#07fc03}{16}\) and add insert the decimal from left calculated in step 2. That means we need to add decimal after \(\textcolor{#07fc03}{16}\)th position

    \[ \begin{aligned} 3919\enspace0000\enspace0000\enspace000 .\\ \implies k = \bold{\textcolor{#07fc03}{3.919\times10^{15}}} \end{aligned} \]

Quickly write the exponential form

Since, we want to put decimal just after 1st digit. We need to move decimal from 16th position to right after 1st digit; which will introduce +ve powers. (\(16 -1 = \textcolor{#07fc03}{15}\)). Since we moved 15 positions left.

\(3.919 \times 10^{\textcolor{#07fc03}{15}}\)